tag:blogger.com,1999:blog-59626343832670363052024-02-08T05:58:56.612-08:00AdiChemistry: Resource of Study Material for AllAditya vardhanhttp://www.blogger.com/profile/06923343055155089267noreply@blogger.comBlogger15125tag:blogger.com,1999:blog-5962634383267036305.post-62246336173350091222021-12-23T08:00:00.001-08:002021-12-23T08:00:21.552-08:00Fischer carbenes - structure - bonding - preparation - reactivity - NTA...<iframe frameborder="0" height="270" src="https://youtube.com/embed/0R2pueqd8Mk" width="480"></iframe><div><br /></div><div><span style="background-color: white; color: #0d0d0d; font-family: Roboto, Noto, sans-serif; font-size: 15px; white-space: pre-wrap;"> Fischer carbenes are the metal carbene complexes formed by electron-rich low oxidation state metals with singlet carbene organic ligands with a double bond between metal and carbene carbon. There is considerable electrophilic nature on carbene carbon due to weak pi back donation from metal to carbon.</span></div><div><span style="background-color: white; color: #0d0d0d; font-family: Roboto, Noto, sans-serif; font-size: 15px; white-space: pre-wrap;"><br /></span></div><div><span style="color: #0d0d0d; font-family: Roboto, Noto, sans-serif;"><span style="background-color: white; font-size: 15px; white-space: pre-wrap;">http://www.adichemistry.com/</span></span></div>Aditya vardhanhttp://www.blogger.com/profile/06923343055155089267noreply@blogger.com0tag:blogger.com,1999:blog-5962634383267036305.post-26290440500115558722018-08-19T09:40:00.005-07:002018-08-19T09:40:42.347-07:00Pearson's Hard Soft Acid Base Theory - AdiChemistry<div style="box-sizing: border-box; color: darkgreen; font-family: verdana, arial; font-size: 12px; margin-bottom: 7px; margin-top: 8px; text-align: justify; text-indent: 3%;">
<b style="box-sizing: border-box;">Hard and Soft Acids and Bases (HSAB) Theory</b> is a qualitative concept introduced by Ralph Pearson to explain the stability of metal complexes and the mechanisms of their reactions. However it is possible to quantify this concept based on Klopman's FMO analysis using interactions between HOMO and LUMO.</div>
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According to this theory, the Lewis acids and bases can be further divided into hard or soft or border line types.</div>
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<b style="box-sizing: border-box;"><span style="box-sizing: border-box; color: maroon;">Hard Lewis acids</span></b> are characterized by small ionic radii, high positive charge, strongly solvated, empty orbitals in the valence shell and with <span style="box-sizing: border-box; color: blue;">high energy LUMOs</span>.</div>
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<b style="box-sizing: border-box;"><span style="box-sizing: border-box; color: #ff0066;">Soft Lewis acids</span></b> are characterized by large ionic radii, low positive charge, completely filled atomic orbitals and with <span style="box-sizing: border-box; color: blue;">low energy LUMOs</span>.</div>
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<b style="box-sizing: border-box;"><span style="box-sizing: border-box; color: maroon;">Hard Lewis bases</span></b> are characterized by small ionic radii, strongly solvated, highly electronegative, weakly polarizable and with <span style="box-sizing: border-box; color: blue;">high energy HOMOs</span>.</div>
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<b style="box-sizing: border-box;"><span style="box-sizing: border-box; color: #ff0066;">Soft Lewis bases</span></b> are characterized by large ionic radii, intermediate electronegativity, highly polarizable and with <span style="box-sizing: border-box; color: blue;">low energy HOMOs</span>.</div>
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The <b style="box-sizing: border-box;"><span style="box-sizing: border-box; color: #990099;">Border line</span></b> Lewis acids and bases have intermediate properties.</div>
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Remember that it is not necessary for Lewis acid or base to possess all the properties to be classified as hard or soft or borderline.</div>
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<i style="box-sizing: border-box;"><b style="box-sizing: border-box;">In short, <span style="box-sizing: border-box; color: maroon;">Hard acids and bases</span> are small and non-polarizable, whereas <span style="box-sizing: border-box; color: magenta;">Soft acids and bases</span> are larger and more polarizable. </b></i></div>
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<b><span style="color: red;">More at:</span></b></div>
<a href="https://www.adichemistry.com/inorganic/cochem/hsab/hard-soft-acid-base-theory.html">https://www.adichemistry.com/inorganic/cochem/hsab/hard-soft-acid-base-theory.html</a>Aditya vardhanhttp://www.blogger.com/profile/06923343055155089267noreply@blogger.com0tag:blogger.com,1999:blog-5962634383267036305.post-21432061713777411332018-06-22T07:45:00.003-07:002018-06-22T07:45:56.480-07:00Wilkinson's catalyst Part-2 - mechanism - catalytic cycle - CSIR NET GAT...<iframe allowfullscreen="" frameborder="0" height="270" src="https://www.youtube.com/embed/Q2lP2tSCcj0" width="480"></iframe>Aditya vardhanhttp://www.blogger.com/profile/06923343055155089267noreply@blogger.com0tag:blogger.com,1999:blog-5962634383267036305.post-87636172181942847952018-06-22T07:45:00.001-07:002018-06-22T07:45:54.540-07:00Wilkinson's catalyst Part-2 - mechanism - catalytic cycle - CSIR NET GAT...<iframe allowfullscreen="" frameborder="0" height="270" src="https://www.youtube.com/embed/Q2lP2tSCcj0" width="480"></iframe>Aditya vardhanhttp://www.blogger.com/profile/06923343055155089267noreply@blogger.com0tag:blogger.com,1999:blog-5962634383267036305.post-41997578091972863512018-03-20T04:47:00.001-07:002018-03-20T04:47:08.377-07:00How to calculate mass of copper deposited at cathode? IIT JEE NEET<iframe allowfullscreen="" frameborder="0" height="270" src="https://www.youtube.com/embed/YwmLdLx8Mss" width="480"></iframe>Aditya vardhanhttp://www.blogger.com/profile/06923343055155089267noreply@blogger.com0tag:blogger.com,1999:blog-5962634383267036305.post-60466733941596999502014-05-21T13:01:00.002-07:002014-05-21T13:01:33.533-07:00Elements and compounds<h3 class="sideh" style="color: #cc0000; font-family: verdana, arial; font-size: 12px; line-height: 16.799999237060547px;">
What is an element?</h3>
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According to modern view, in simpler terms, an <b>element</b> can be defined as a substance made up of atoms of same atomic number.</div>
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For example, hydrogen gas, H<sub>2</sub> is an element since the atoms in it have the same atomic number i.e. 1. </div>
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<span style="color: magenta;"><b>FIND MORE INFORMATION AT</b></span></div>
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<b><span style="color: #0b5394; font-family: Verdana, sans-serif; font-size: x-small;"><a href="http://www.adichemistry.com/general/chemistry-basics/elem/elements-compounds.html">http://www.adichemistry.com/general/chemistry-basics/elem/elements-compounds.html</a></span></b></div>
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<span style="color: darkgreen; font-family: verdana, arial; font-size: 12px; line-height: 16.799999237060547px; text-align: justify; text-indent: 3%;">A chemical compound consists of two are more different types of atoms. For example, water is a compound made up of hydrogen and oxygen. Its formula is H</span><sub style="color: darkgreen; font-family: verdana, arial; line-height: 16.799999237060547px; text-align: justify; text-indent: 3%;">2</sub><span style="color: darkgreen; font-family: verdana, arial; font-size: 12px; line-height: 16.799999237060547px; text-align: justify; text-indent: 3%;">O i.e., there are two hydrogen atoms per every oxygen atom.</span></div>
Aditya vardhanhttp://www.blogger.com/profile/06923343055155089267noreply@blogger.com0tag:blogger.com,1999:blog-5962634383267036305.post-49041390055032947542014-05-19T18:22:00.000-07:002014-05-19T18:22:22.209-07:00Electrolysis at adichemistry<div style="color: darkgreen; font-family: verdana, arial; font-size: 12px; line-height: 16.799999237060547px; margin-bottom: 7px; margin-top: 8px; text-align: justify; text-indent: 3%;">
<b>Electrolysis</b> involves dissociation (lysis) of an electrolyte by using a direct electric current. In this process, electrical energy is used to carryout a non-spontaneous redox chemical reaction. </div>
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The setup used to serve this purpose is known as electrolytic cell.</div>
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Read more at: </div>
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<span style="color: #3d85c6; font-family: verdana, arial;"><span style="font-size: 12px; line-height: 16.799999237060547px;"><b>http://www.adichemistry.com/physical/electrochemistry/electrolysis/electrolysis.html</b></span></span></div>
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<img alt="electrolytic cell - a schematic representation" border="0" height="457" src="http://www.adichemistry.com/physical/electrochemistry/electrolysis/electrolytic-cell.png" width="504" /></div>
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<span style="color: darkgreen; font-family: verdana, arial;"><span style="font-size: 12px; line-height: 16.799999237060547px;"><a href="http://www.adichemistry.com/index.html">http://www.adichemistry.com/index.html</a></span></span></div>
Aditya vardhanhttp://www.blogger.com/profile/06923343055155089267noreply@blogger.com0tag:blogger.com,1999:blog-5962634383267036305.post-87010679712388235092013-05-01T11:20:00.001-07:002013-05-01T11:20:08.406-07:00HYDROGEN BONDING<i>The electrostatic force of attraction between partially positively charged hydrogen in a polar molecule and an electronegative atom is called <b>hydrogen bond</b>.</i><br />
It is represented by dotted line as shown below.<br />
<div class="ind">H--------X</div>where X is an electronegative atom.<br />
<b><span style="color: #cc0000;">Characteristics of Hydrogen bond </span></b><br />
1) The nature of H-bonding is purely electrostatic.<br />
2) The hydrogen atom must be covalently bonded to a highly electronegative atom in order to acquire sufficient positive charge to participate in hydrogen bonding.<br />
3) The electronegative atom should possess high charge density so as to attract positively charged hydrogen atom effectively. Thus H-bonding is observed with smaller and highly electronegative atoms such as F, O and N.<br />
4) The hydrogen bond is stronger than van der Waal's forces of attraction. However it is weaker than the <a href="http://www.blogger.com/covalentbond/covalent-bond.html"> covalent bond</a> and <a href="http://www.blogger.com/ionicbond/ionic-bond.html"> ionic bond</a>.<br />
5) The strength of H- bond is directly proportional to the electronegativity of electronegative atom. Thus the strengths of hydrogen bonds with different electronegative atoms varies as follows:<br />
H------F > H------O > H-------N<br />
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Read more at: <a href="http://www.adichemistry.com/general/chemicalbond/hbond/hydrogen-bonding.html">HYDROGEN BONDING</a>Aditya vardhanhttp://www.blogger.com/profile/06923343055155089267noreply@blogger.com0tag:blogger.com,1999:blog-5962634383267036305.post-5696800144425527082013-04-30T17:02:00.001-07:002013-04-30T17:02:11.391-07:00ETHYL CHLORIDE | ALCOHOLIC KOH | ELIMINATION | DEHYDROHALOGENATION<br />
<div class="Q">
Why elimination occurs instead of nucleophilic substitution when ethyl chloride reacts with alcoholic potassium hydroxide?</div>
<div class="Q">
Explanation:</div>
Ethyl chloride can undergo both nucleophilic substitution as well as elimination reactions with strong alkali like KOH.<br />
When it undergoes nucleophilic substitution, ethyl alcohol is formed as major product.<br />
More at:<br />
<a href="http://www.adichemistry.com/qb/organic/mechanism/2-ethylchloride-KOH.html">ETHYL CHLORIDE | ALCOHOLIC KOH | ELIMINATION | DEHYDROHALOGENATION</a><br />
Aditya vardhanhttp://www.blogger.com/profile/06923343055155089267noreply@blogger.com0tag:blogger.com,1999:blog-5962634383267036305.post-14346569480665292972013-04-02T03:20:00.001-07:002013-04-02T03:20:20.837-07:00 aldehydes with no alpha hydrogen give cannizaro reaction Adi Chemistry Homework help forum<a href="http://www.adichemistry.com/forum/viewtopic.php?f=3&t=104#.UVqwqFfnsoF.blogger">View topic - aldehydes with no alpha hydrogen give cannizaro reaction Adi Chemistry Homework help forum</a>Aditya vardhanhttp://www.blogger.com/profile/06923343055155089267noreply@blogger.com0tag:blogger.com,1999:blog-5962634383267036305.post-56458283093939424212012-11-11T01:14:00.002-08:002012-11-20T08:00:33.382-08:00200 solved problems in advanced organic synthesis for CSIR NET & GATE exams<span style="color: #274e13;"><span style="font-family: 'Lucida Grande', Verdana, Arial, sans-serif; font-size: 13px; line-height: 16.78333282470703px; text-align: justify;">As promised, the “Solved Problems in Advanced Organic Synthesis” book for CSIR NET & GATE exams is updated with 200 problems and is available freely to those who have purchased it previously. However, the rate is now revised to Rs. 875/-. Please download your updated version from the link I have provided at the time of purchase. Please mail me for the new password.</span><br style="font-family: 'Lucida Grande', Verdana, Arial, sans-serif; font-size: 13px; line-height: 16.78333282470703px; text-align: justify;" /><span style="font-family: 'Lucida Grande', Verdana, Arial, sans-serif; font-size: 13px; line-height: 16.78333282470703px; text-align: justify;">Further updates are NOT free. I have changed the policy. You need to participate in the discussions and help me to get further updates. Mail me for further details.</span></span><br />
<a href="https://docs.google.com/open?id=0B3Q1E9g92sO0OFVHZzltclJHRnM" style="font-family: 'Lucida Grande', Verdana, Arial, sans-serif; font-size: 13px; line-height: 16.78333282470703px; text-align: justify; text-decoration: initial;" target="_parent" title="Check sample copy of Solved Problems in Advanced Organic Synthesis bookat Google docs"><span style="color: blue;">Click here to check the sample copy of Solved Problems in Advanced Organic Synthesis at Google docs</span></a>Aditya vardhanhttp://www.blogger.com/profile/06923343055155089267noreply@blogger.com0tag:blogger.com,1999:blog-5962634383267036305.post-85554234146441688762012-07-21T19:06:00.003-07:002012-11-21T19:06:21.426-08:00Solved Problems in Advanced Organic synthesis for CSIR NET & GATE exams<br />
<b><span style="color: #351c75;">Now the number of problems in solved problems in advanced organic </span><span style="background-color: white;"><span style="color: #351c75;">synthesis book is: </span><span style="color: red; font-size: large;">200</span><span style="color: #351c75;">.</span></span></b><br />
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Find it at: <a href="https://docs.google.com/open?id=0B3Q1E9g92sO0OFVHZzltclJHRnM">https://docs.google.com/open?id=0B3Q1E9g92sO0OFVHZzltclJHRnM</a> <span style="background-color: white;">( for free viewing)</span><br />
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<h3 style="text-align: left;">
<b style="color: magenta;">You may also download a free sample copy from:</b></h3>
<a href="http://www.slideshare.net/adichemadi/solved-problems-in-advanced-organic-synthesis">http://www.slideshare.net/adichemadi/solved-problems-in-advanced-organic-synthesis</a><br />
or<br />
<a href="http://www.wiziq.com/tutorial/314462-SOLVED-PROBLEMS-IN-ADVANCED-ORGANIC-SYNTHESIS">http://www.wiziq.com/tutorial/314462-SOLVED-PROBLEMS-IN-ADVANCED-ORGANIC-SYNTHESIS</a><br />
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You may update your copy from: (for those who have purchased)<br />
<a href="https://docs.google.com/open?id=0B3Q1E9g92sO0VmtueDIxTWZOZmM">https://docs.google.com/open?id=0B3Q1E9g92sO0VmtueDIxTWZOZmM</a><br />
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<br />Aditya vardhanhttp://www.blogger.com/profile/06923343055155089267noreply@blogger.com2tag:blogger.com,1999:blog-5962634383267036305.post-43820430247906867852011-03-23T10:38:00.000-07:002012-06-10T19:55:52.057-07:00Basic introduction to concepts in organic chemistry at adichemistry<div style="color: darkgreen; font-family: verdana, arial; font-size: 12px; line-height: 16px; margin-bottom: 7px; margin-top: 8px; text-indent: 3%;">
Let us start with the question <b>"What is Organic chemistry?"</b>.</div>
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The simple answer is: It is the <b>chemistry of carbon containing compounds</b>, which are otherwise known as organic compounds.</div>
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So it is pretty easy to recognize that we should start our journey of <i>organic chemistry</i> by exploring the chemical nature of <b>carbon</b>.</div>
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So the next question is: <b>What is carbon?</b></div>
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* <b>Carbon</b> is an element with <b>atomic number (Z) = 6</b>.</div>
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* Its ground state electronic configuration can be represented as: <b>1s<sup>2</sup>2s<sup>2</sup>2p<sup>2</sup></b> (or) <b>1s<sup>2</sup>2s<sup>2</sup>2p<sub>x</sub><sup>1</sup>2p</b><b><sub>y</sub><sup>1</sup></b><b>2p<sub>z</sub></b><b><sup>0</sup></b></div>
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Get more information at: </div>
<div style="color: darkgreen; font-family: verdana, arial; font-size: 12px; line-height: 16px; margin-bottom: 7px; margin-top: 8px; text-indent: 3%;">
<a href="http://www.adichemistry.com/organic/basics/introduction/organic-chemistry-introduction.html" style="color: #2288bb; text-decoration: none;">http://www.adichemistry.com/organic/basics/introduction/organic-chemistry-introduction.html</a></div>Aditya vardhanhttp://www.blogger.com/profile/06923343055155089267noreply@blogger.com0tag:blogger.com,1999:blog-5962634383267036305.post-10256227780543647382011-03-18T21:10:00.000-07:002011-03-18T21:10:11.350-07:00Wurtz reaction at adichemistry<div style="font-family: verdana, arial; font-size: 12px; line-height: 16px; margin-bottom: 7px; margin-top: 8px; text-indent: 3%;"><a href="http://www.adichemistry.com/organic/namedreactions/wurtz/wurtz-reaction-1.html"><b><span class="Apple-style-span" style="color: #351c75;">EXCERPTS OF WURTZ REACTION FROM ADICHEMISTRY.COM</span></b></a></div><div style="color: darkgreen; font-family: verdana, arial; font-size: 12px; line-height: 16px; margin-bottom: 7px; margin-top: 8px; text-indent: 3%;"><br />
</div><div style="color: darkgreen; font-family: verdana, arial; font-size: 12px; line-height: 16px; margin-bottom: 7px; margin-top: 8px; text-indent: 3%;">* In <b>Wurtz </b>reaction, two alkyl halide molecules are coupled in presence of sodium metal in anhydrous ether or tetrahydrofuran to form a new carbon carbon bond and thus by giving a symmetrical alkane.</div><div class="RXN" style="color: darkgreen; font-family: verdana, arial; font-size: 12px; left: 6%; line-height: 16px; position: relative;"><table border="0" cellpadding="0" cellspacing="0" class="RXN" style="border-bottom-color: initial; border-bottom-style: none; border-bottom-width: initial; border-left-color: initial; border-left-style: none; border-left-width: initial; border-right-color: initial; border-right-style: none; border-right-width: initial; border-top-color: initial; border-top-style: none; border-top-width: initial; color: darkgreen; empty-cells: show; font-family: Verdana, Arial; font-size: 12px; text-align: center;"><tbody>
<tr><td class="RXNB" style="border-bottom-color: rgb(255, 140, 0); border-bottom-style: none; border-bottom-width: 1px; border-color: initial; border-left-color: initial; border-left-style: none; border-left-width: initial; border-right-color: rgb(255, 140, 0); border-right-style: none; border-right-width: 1px; border-top-color: initial; border-top-style: none; border-top-width: initial; border-width: initial; color: blue;" valign="middle"></td><td class="RXNB" style="border-bottom-color: rgb(255, 140, 0); border-bottom-style: none; border-bottom-width: 1px; border-color: initial; border-left-color: initial; border-left-style: none; border-left-width: initial; border-right-color: rgb(255, 140, 0); border-right-style: none; border-right-width: 1px; border-top-color: initial; border-top-style: none; border-top-width: initial; border-width: initial; color: blue;" valign="middle">Dry Ether</td><td class="RXNB" style="border-bottom-color: rgb(255, 140, 0); border-bottom-style: none; border-bottom-width: 1px; border-color: initial; border-left-color: initial; border-left-style: none; border-left-width: initial; border-right-color: rgb(255, 140, 0); border-right-style: none; border-right-width: 1px; border-top-color: initial; border-top-style: none; border-top-width: initial; border-width: initial; color: blue;" valign="middle"></td></tr>
<tr><td class="RXNB" style="border-bottom-color: rgb(255, 140, 0); border-bottom-style: none; border-bottom-width: 1px; border-color: initial; border-left-color: initial; border-left-style: none; border-left-width: initial; border-right-color: rgb(255, 140, 0); border-right-style: none; border-right-width: 1px; border-top-color: initial; border-top-style: none; border-top-width: initial; border-width: initial; color: blue;" valign="middle">R-X + 2Na + X-R</td><td class="RXNB" style="border-bottom-color: rgb(255, 140, 0); border-bottom-style: none; border-bottom-width: 1px; border-color: initial; border-left-color: initial; border-left-style: none; border-left-width: initial; border-right-color: rgb(255, 140, 0); border-right-style: none; border-right-width: 1px; border-top-color: initial; border-top-style: none; border-top-width: initial; border-width: initial; color: blue;" valign="middle"> -----------------> </td><td class="RXNB" style="border-bottom-color: rgb(255, 140, 0); border-bottom-style: none; border-bottom-width: 1px; border-color: initial; border-left-color: initial; border-left-style: none; border-left-width: initial; border-right-color: rgb(255, 140, 0); border-right-style: none; border-right-width: 1px; border-top-color: initial; border-top-style: none; border-top-width: initial; border-width: initial; color: blue;" valign="middle"> R-R + 2NaX </td></tr>
<tr><td class="RXN" style="border-bottom-color: rgb(255, 140, 0); border-bottom-style: none; border-bottom-width: 1px; border-color: initial; border-left-color: initial; border-left-style: none; border-left-width: initial; border-right-color: rgb(255, 140, 0); border-right-style: none; border-right-width: 1px; border-top-color: initial; border-top-style: none; border-top-width: initial; border-width: initial; color: maroon;" valign="middle"></td><td class="RXN" style="border-bottom-color: rgb(255, 140, 0); border-bottom-style: none; border-bottom-width: 1px; border-color: initial; border-left-color: initial; border-left-style: none; border-left-width: initial; border-right-color: rgb(255, 140, 0); border-right-style: none; border-right-width: 1px; border-top-color: initial; border-top-style: none; border-top-width: initial; border-width: initial; color: maroon;" valign="middle"></td><td class="RXN" style="border-bottom-color: rgb(255, 140, 0); border-bottom-style: none; border-bottom-width: 1px; border-color: initial; border-left-color: initial; border-left-style: none; border-left-width: initial; border-right-color: rgb(255, 140, 0); border-right-style: none; border-right-width: 1px; border-top-color: initial; border-top-style: none; border-top-width: initial; border-width: initial; color: maroon;" valign="middle"></td></tr>
</tbody></table></div><div style="color: darkgreen; font-family: verdana, arial; font-size: 12px; line-height: 16px; margin-bottom: 7px; margin-top: 8px; text-indent: 3%;">Where X = halogen</div><div style="color: darkgreen; font-family: verdana, arial; font-size: 12px; line-height: 16px; margin-bottom: 7px; margin-top: 8px; text-indent: 3%;">* The Wurtz reaction must be performed under anhydrous conditions because the alkyl free radical formed (see the mechanism) during the reaction is strongly basic and can abstract proton from water.</div><div style="color: darkgreen; font-family: verdana, arial; font-size: 12px; line-height: 16px; margin-bottom: 7px; margin-top: 8px; text-indent: 3%;">* In case of alkyl and aryl fluorides as well as aryl chlorides, tetrahydrofuran is used as solvent instead of ether. </div><div style="color: darkgreen; font-family: verdana, arial; font-size: 12px; line-height: 16px; margin-bottom: 7px; margin-top: 8px; text-indent: 3%;">* The Wurtz reaction is limited to synthesis of symmetrical alkanes with even number of carbon atoms only. The number of carbons in the alkane is double that of alkyl halide (n ---> 2n type reaction)</div><div style="color: darkgreen; font-family: verdana, arial; font-size: 12px; line-height: 16px; margin-bottom: 7px; margin-top: 8px; text-indent: 3%;">* If dissimilar alky halides are used, a mixture of alkanes is formed. It is usually difficult to separate the mixture and hence wurtz reaction not a suitable method to synthesize unsymmetrical alkanes.</div><div style="color: darkgreen; font-family: verdana, arial; font-size: 12px; line-height: 16px; margin-bottom: 7px; margin-top: 8px; text-indent: 3%;">E.g. The Wurtz reaction between R-X and R'-X yields not only R-R' but also R-R and R'-R'. This mixture cannot be separated easily.</div><div style="color: darkgreen; font-family: verdana, arial; font-size: 12px; line-height: 16px; margin-bottom: 7px; margin-top: 8px; text-indent: 3%;">* Methane cannot be prepared by this method.</div><div style="color: darkgreen; font-family: verdana, arial; font-size: 12px; line-height: 16px; margin-bottom: 7px; margin-top: 8px; text-indent: 3%;">* A modification of this reaction involving alkyl and aryl halides is called <b><a href="http://www.adichemistry.com/organic/namedreactions/wurtzfittig/wurtz-fittig-1.html" style="color: #0080ff; text-decoration: none;">Wurtz-Fittig</a></b> reaction. If only aryl halides are subjected to coupling, the reaction is called as <b><a href="http://www.adichemistry.com/organic/namedreactions/fittig/fittig-reaction-1.html" style="color: #0080ff; text-decoration: none;">Fittig</a></b> reaction.</div><div style="color: darkgreen; font-family: verdana, arial; font-size: 12px; line-height: 16px; margin-bottom: 7px; margin-top: 8px; text-indent: 3%;"><br />
</div>Aditya vardhanhttp://www.blogger.com/profile/06923343055155089267noreply@blogger.com0tag:blogger.com,1999:blog-5962634383267036305.post-7341402733360366062011-02-26T20:33:00.000-08:002011-02-26T20:36:13.881-08:00AdiChemistry Blog launchedLaunched the Adichemistry Blog. Updates for my site <a href="http://www.adichemistry.com/">http://www.adichemistry.com/</a> will be available here.<br />
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